Assignment 4 | Carson Alonzo

A1. Conditionals.

1. Declare and assign a value to x. If x is 3, print "x === 3". Add an else clause. It prints "x===4". Alas, your program has a bug: if x is 5 it still prints "x === 4"!

   let text = "";
   let x = 5;

   Incorrect conditional construct

   if (x === 3) {
        text = "x = 3";
   }
   else {
        text = "x = 4";
   }

   This prints:

2. Fix the bug with an "else if" construct, so that now, if x is 4 it correctly prints "x===4" but on the other hand if x is not 4 it correctly prints "x != 4".

   let text = "";
   let x = 5;

   Correct conditional construct

   if (x === 3) {
        text = "x = 3";
   }
   elseif (x === 4) {
        text = "x = 4";
   }
   else{
        text = "x != 4";
   }
   

   This prints:

A2. More conditionals.
1. Demonstrate the if statement using a button.
This button will print "This number is 5" if the number is 5
2. Demonstrate the if else statement using a button.
This button will print "This number is not 5" until it lands on 5
3. Demonstrate the "else if" statement (an if else statement in which the else clause is another if else statement) using a button.
This button will print "This number is 5" if the number is 5

A3. Implement a for loop, a while loop, and a do while loop. These should involve buttons that demonstrate the loops.

This button increments a number until it reaches 10 using a for loop
This button uses a while loop to demonstrate the Collatz Conjecture
This button prints "Printing" + number while number is less than 10

A4. Modify the button styles. Here is an example: (check the source code for this button to see how it is done).